Published on: 2025-05-05 18:46:00
How Liverpool's title win has completed a mysterious Fibonacci sequence 4 days ago Share Save Kit Yates Share Save Getty Images Liverpool FC's victory at the weekend has clinched them their second Premier League title but it also resulted in something curious – producing a strange series of numbers in the league's record books. Something remarkable has just happened in English football. Liverpool FC have been crowned Premier League champions for a second time. When added to their 18 pre-Prem
Keywords: fibonacci league premier sequence theory
Find related items on AmazonPublished on: 2025-06-23 02:39:06
How Europe is reacting to 'dire' consequences from US tariff Katya Adler BBC Europe editor European Commission chief Ursula von der Leyen spoke on behalf of all EU countries when she said the new tax imports would cause "dire" consequences for millions of people around the globe. She said there was no clear path through what she called the chaos and complexity the new Trump tariffs would unleash worldwide. But the Commission has promised to protect EU business - some of which will be more h
Keywords: called consequences eu said trump
Find related items on AmazonPublished on: 2025-06-30 06:53:33
2025-03-30 What's faster than Memcmp? In this post I look at improvements in .NET and using Span for performance and portability. I was examining portability issues in a code base that I wanted to migrate from .NET framework 4.8.1 to .NET8. I discovered use of msvcrt.dll . I quickly established it is a popular stackoverflow answer for a fast way to compare byte arrays in .NET The answer as provided, and faithfully copied into codebases, is this: [ DllImport ( "msvcrt.dll" , CallingConvention
Keywords: 00 framework net ns sequenceequal
Find related items on AmazonPublished on: 2025-07-15 13:55:13
COMMENTS Are there any more terms in this sequence? Evidence that the sequence may be finite, from Rick L. Shepherd , Jun 23 2002: 1) The sequence of last two digits of 2^n, A000855 of period 20, makes clear that 2^n > 4 must have n == 3, 6, 10, 11, or 19 (mod 20) for 2^n to be a member of this sequence. Otherwise, either the tens digit (in 10 cases), as seen directly, or the hundreds digit, in the 5 cases receiving a carry from the previous power's tens digit >= 5, must be odd. 2) No additi
Keywords: 10 additional digit digits sequence
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